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SN65LVDS306: behaviour of CPOL

Part Number: SN65LVDS306

The Datasheet specifies on Page 6 the following for the input pin CPOL:

0 - rising edge clocking

1 - falling edge clocking

Whereas Figure 4 on Page 8 shows, that the data is clocked out with the falling edge if CPOL = 0. At least the Comment in brackets implies it (CPOL=0)

What is the correct behaviour of CPOL?

Thanks for your help